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VOLUME 56 (1992) | ISSUE 7 | PAGE 345
Axial-anomaly pole and spontaneous breaking of chiral symmetry
There is no factorization of vertices for an axial-anomaly pole. Consequently, a Goldstone boson coupled with a spontaneous breaking of chiral symmetry cannot reproduce an axial-anomaly pole. The possibility of introducing a massless Goldstone pseudoscalar boson, along with a massless pseudovector boson, is discussed.